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Article posted by
Naimishforu on 6/26/2011 | Views: 4224 | Category:
C# | Level: Intermediate |
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In this article I shall demonstrate the exception-handling capabilities of C#.
Introduction
After
finishing the
Part 1, let's
create a program that will demonstrate the exception-handling capabilities of
C#.
This program will define an array that contains only one
element.
The program will then prompt the user to enter a 0 or a 1. If 0 is
entered, program execution performs as expected and the element at an index of
zero in the array will be displayed on screen. If 1 is entered, an exception
will be thrown, as there is no corresponding index in the array.
Step 1 of 4
The Main method of this program may throw an exception.
Enter the keyword that marks the code the program will attempt to
execute.
using System;
namespace Exceptions
{
class ExceptionHandlingTest
{
static void Main(string[] args)
{
int[] intArray = {100};
MISSING CODE (You will have to enter TRY Block over here)
}
}
}
Result
You type try, which encloses the code in a method that is to be
executed but may throw an exception.
Step 2 of 4
The try block contains code that will be executed and may throw an
exception.
What will the program do if an exception is thrown?
using System;
namespace Exceptions
{
class ExceptionHandlingTest
{
static void Main(string[] args)
{
int[] intArray = {100};
try
{
MISSING CODE (You will have to enter proper Catch Block)
}
}
}
}
Result
If an exception is thrown, the program will unwind the assembly
until it finds a catch statement that contains an appropriate exception
handler.
Step 3 of 4
To signal an abnormal condition on C#, you throw an exception.
Enter the line of code that creates an instance of
System.Exception.
using System;
namespace Exceptions
{
class ExceptionHandlingTest
{
static void Main(string[] args)
{
int[] intArray = {100};
try
{
Console.WriteLine("Enter 0 for an Exception ");
Console.WriteLine("Enter 1 for IndexOutOfRangeException");
int index = Int32.Parse(Console.ReadLine());
Console.WriteLine("Number is {0}", intArray[index].ToString());
MISSING CODE; (You can choose any line of code from the Results below)
}
}
}
}
Result
In fact, you can use any of the following lines of code to create
an instance of System.Exception:
throw new Exception()
throw new System.Exception()
throw new Exception( )
throw new System.Exception( )
throw new Exception()
throw new System. Exception()
Step 4 of 4
The array described in this program contains only one element.
Which exception will be thrown if the user chooses an element that
isn't part of the array?
Result
If the user tries to choose an element that isn't part of the
array, the IndexOutOfRangeException exception is thrown.
The following is the output of this program when the user enters
0.
Enter 0 for an Exception
Enter 1 for IndexOutOfRangeException
0
Number is 100
Exception of type System.Exception was thrown.
There is only one element in this array: 100
And this is the output if the user enters 1.
Enter 0 for an Exception
Enter 1 for IndexOutOfRangeException
1
IndexOutOfRangeException caught,
an index of 1 does not exist in the array!
There is only one element in this array: 100
Thanks for reading.
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