Set Page Position after asyncPostback in AJAX

Virendradugar
Posted by in ASP.NET AJAX category on for Beginner level | Views : 21125 red flag

This article explains a simple trick to set the page position to any coordinates after async Postback.
Introduction
I will start this article, with one of the problem which I come across recently.

Background

I was working with a page. The page is divided into two parts.

1. Add/Update/Delete (I call it Area 1)
2. Listing of records (I call it Area 2)

I have used Repeater control with no paging (Though the records are more but my client hates paging.). Above the repeater control, there were some textbox, dropdowns, checkbox, listbox etc. were placed used for add/update operations. There is a link button in the repeater control for every row, which when clicked opens the records in update mode. It fills all the control with data placed on Area.
 
Everything is placed in an UpdatePanel.

Problem

There were more than 10000 records listed in the repeater. When I click the very last record for editing, asynchronous postback happens and data is loaded for editing in Area 1 . But the problem was with the page position. I was not able to see the control's of Part1, as page was maintaining it's scroll position after async postback. This is what I don't want. As it's not at all user friendly. End-User will never come to know that record has been opened in edit mode. I set the "MaintainScrollPositionOnPostback" property to false but it was not working due to AJAX. Somehow, I want page position to be set to (0,0) so that I can see Area 1 controls.

Solution

The solution was to set Page position back to 0,0, at the end of ajax request. Here is what I did. See below code.
 <script type="text/javascript">
    var prm = Sys.WebForms.PageRequestManager.getInstance();
    prm.add_endRequest(EndRequestHandler);
    function EndRequestHandler(sender, args) {         window.scroll(0,0);    } </script>
Javascript provides a function scroll() which basically scrolls page position to the specified value. It takes two arguments Top and left. I passed it 0,0 and it worked for me.

Enjoy..
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About the Author

Virendradugar
Full Name: Virendra Dugar
Member Level: Silver
Member Status: Member,MVP
Member Since: 8/11/2009 4:14:05 AM
Country: India

http://jquerybyexample.blogspot.com
Virendra Dugar is experienced Senior Software Developer with over 5 years of hands-on experience working with Microsoft .NET technology (ASP.NET, C#, VB.NET,SQL Server). He is always keen to learn new technology. He holds a Master's Degree in Computer Application & Information technology from Gujarat University in india.In free time, he loves to listen music, read books, play games and do blogging etc. Visit his blogs : http://jquerybyexample.blogspot.com

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