How to generate random numbers with Linq

Goldytech
Posted by Goldytech under LINQ category on | Views : 4405
This snippet shows you how you can generate the random numbers of any range

private List<int> GetRandomNumbers()
{
Random rnd = new Random();
List<int> numbers;
numbers= Enumerable.Range(1, 10).OrderBy(z=> rnd.Next()).ToList() ;
return numbers;
}


The above code generate the random numbers between 1 to 10

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