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# Multiply a number without using the '*' operator.

Interview question and answer by: Dotnetrajanikanth | Posted on: 4/18/2012 | Category: Others Interview questions | Views: 961 | | Points: 40

Answer:

Simplest answer that i could give is

for(i=0;i<n;i++)
{
num = num+num
}

Hope this helps...

Source: Experience | Asked In: interview |
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## Responses

Posted by: Dotnetrajanikanth | Posted on: 19 Apr 2012 01:35:51 AM | Points: 10 |

The same idea can be used to implement division also

Posted by: Dhiren.Kaunar@Gmail.Com | Posted on: 19 Apr 2012 01:56:44 AM | Points: 10 |

Hi,

The above code will return wrong result
Ex : if will execute with assumtion n=2 and num=3
for(i=0;i<n;i++)
{
num = num+num
}

i=0 num=6
i=1 num=12

it will resolve if will use third variable
res=0
for(i=0;i<n;i++)
{
res+=num ;
}
i=0 res=3
i=1 , res=6
BUt the above condition will be fail if we have -ve number
Hope the below code will help.
int num = -5, i, num2 = -3;
int res=0;
int negCtr = 0;

if (num < 0)
{
num = num * -1;
negCtr++;
}
if (num2 < 0)
{
num2 = num2 * -1;
negCtr++;
}

for (i = 0; i < num2; i++)
{
res += num;
}
if (negCtr == 1)
{
res = res * -1;

}

Thanks,
Dhiren

Posted by: Stefanstaev | Posted on: 19 Apr 2012 04:07:24 AM | Points: 10 |

Hope this helps... - this is not helpfull. I am reading a lot of "spam" articles in the last months.

Posted by: Dotnetrajanikanth | Posted on: 19 Apr 2012 04:39:43 AM | Points: 10 |

Thank you for pointing out the error...

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