using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Data;
using System.Data.SqlClient;
public partial class UploadImage : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
Button1 .Text ="click me";
}
protected void Button1_Click(object sender, EventArgs e)
{
if (FileUpload1.PostedFile != null && FileUpload1.PostedFile.FileName != "")
{
byte[] myimage = new byte[FileUpload1.PostedFile.ContentLength];
HttpPostedFile Image = FileUpload1.PostedFile;
Image.InputStream.Read(myimage, 0, (int)FileUpload1.PostedFile.ContentLength);
SqlConnection myConnection = new SqlConnection(ConfigurationSettings.AppSettings["connection"].ToString());
myConnection.Open();
SqlCommand storeimage = new SqlCommand("INSERT INTO guest.Photos"
+ "(Picture) "
+ " values ( @Picture)", myConnection);
storeimage.Parameters.Add("@Picture", SqlDbType.Image, myimage.Length).Value = myimage;
storeimage.Parameters["@Picture"].Value = myimage;
storeimage.ExecuteNonQuery();
Button1.Text = "image inserted sucessfully";
}
}
}
Syed Shakeer Hussain
Amansandha, if this helps please login to Mark As Answer. | Alert Moderator