object reference does not set to an instance of object

Posted by Amritha444 under C# on 3/2/2012 | Points: 10 | Views : 2185 | Status : [Member] | Replies : 3

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Hi all

Please check my code

MainMenu first_menu = new MainMenu();
this.Menu = first_menu;

MenuItem[] secondMenu = new MenuItem[2];
MenuItem menu = new MenuItem(row["CategoryId"].ToString());
secondMenu[0] = menu;

MenuItem Parent_menu = new MenuItem( row["Name_tb"].ToString(), secondMenu);

error happening as object reference does not set to an instance of object

What may be the reason,how to pass value field of menu item in windows application other than this method

Thanks in Advance

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Posted by: Naraayanan on: 3/5/2012 [Member] Starter | Points: 25

0	Hi, Could you upload your code ?Please tell me .what is the purpose of row using in your code? Regards, Lakshmi Naraayanan.S http://dotnettechrocks.blogspot.in/ http://abaprocker.blogspot.com/ Amritha444, if this helps please login to Mark As Answer. \| Alert Moderator

Posted by: Blueskysinger on: 3/7/2012 [Member] Starter | Points: 25

0	i dont follow you. do you mean like a barcode generator?like this?http://www.keepautomation.com/csharp_barcode/2d_barcodes.html Anna White Amritha444, if this helps please login to Mark As Answer. \| Alert Moderator

Posted by: Hmanjarawala on: 3/7/2012 [Member] Bronze | Points: 25

0	Hi Amitha, Try this MainMenu first_menu = new MainMenu(); this.Menu = first_menu; MenuItem[] secondMenu = new MenuItem[2]; MenuItem menu = new MenuItem(row["CategoryId"].ToString()); secondMenu[0] = menu; secondMenu[1] = new MenuItem(""); MenuItem Parent_menu = new MenuItem( row["Name_tb"].ToString(), secondMenu); Himanshu Manjarawala Sr. Software Engineer@AutomationAnywhere http://fieredotnet.wordpress.com/ Amritha444, if this helps please login to Mark As Answer. \| Alert Moderator

Hi Amitha, Try this


MainMenu first_menu = new MainMenu();

this.Menu = first_menu;



MenuItem[] secondMenu = new MenuItem[2];

MenuItem menu = new MenuItem(row["CategoryId"].ToString());

secondMenu[0] = menu;



secondMenu[1] = new MenuItem("");



MenuItem Parent_menu = new MenuItem( row["Name_tb"].ToString(), secondMenu);

Himanshu Manjarawala
Sr. Software Engineer@AutomationAnywhere
http://fieredotnet.wordpress.com/

Amritha444, if this helps please login to Mark As Answer. | Alert Moderator

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