Dear all
when user click on insert linke button, response it by label lblFeedbackok so how can do it ?
protected void InsertButton_Click(object sender, EventArgs e)
{
try
{
FormViewNewscomment.ItemInserted();
Button InsertButton = (Button)FormViewNewscomment.FindControl("InsertButton");
Label lblProfileOK = (Label)FormViewNewscomment.FindControl("lblProfileOK");
lblProfileOK.Visible = true;
}
catch (Exception except)
{
// Handle the Exception.
Label lblProfileko = (Label)FormViewNewscomment.FindControl("lblProfileko");
lblProfileko.Visible = true;
}
}
<asp:FormView ID="FormViewNewscomment" runat="server" Width="100%" DataSourceID="AccessDataSourcecomment" DefaultMode="Insert" ...
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