MSSQL Version
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declare @t table([DATE] DATE,LEAVEDAYS Varchar(10),NXTWRKDAYS DATE)
insert into @t Values
('2014-07-01','No',NULL),
('2014-07-02','No',NULL),
('2014-07-03','No',NULL),
('2014-07-04','No',NULL),
('2014-07-05','Yes',NULL),
('2014-07-06','Yes',NULL),
('2014-07-07','Yes',NULL),
('2014-07-08','No',NULL)
SELECT
t.date AS Date,
t.leavedays AS LeaveDays,
CASE WHEN t.LEAVEDAYS = 'No' THEN DATEADD(day,1, t.DATE)
WHEN t.LEAVEDAYS = 'Yes' THEN (Select top 1 t1.date from @t t1 WHERE t1.date > t.DATE and t1.LEAVEDAYS = 'No' ORDER BY t1.date)
ELSE null END AS NxtWorkingDay
FROM @t t
Output
---------
Date LeaveDays NxtWorkingDay
2014-07-01 No 2014-07-02
2014-07-02 No 2014-07-03
2014-07-03 No 2014-07-04
2014-07-04 No 2014-07-05
2014-07-05 Yes 2014-07-08
2014-07-06 Yes 2014-07-08
2014-07-07 Yes 2014-07-08
2014-07-08 No 2014-07-09
If you are using MySQL, please use
DATE_ADD() (
http://www.w3schools.com/sql/func_date_add.asp ) instead of
DATEADD function of SQL Server.
Hope that helps.
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Thanks & Regards,
RNA Team
Jayakumars, if this helps please login to Mark As Answer. | Alert Moderator